| 1 | -module(hope_list). |
| 2 | |
| 3 | -export_type( |
| 4 | [ t/1 |
| 5 | ]). |
| 6 | |
| 7 | -export( |
| 8 | [ unique_preserve_order/1 |
| 9 | , map/2 |
| 10 | , map/3 % Tunable recursion limit |
| 11 | , map_rev/2 |
| 12 | , map_slow/2 |
| 13 | , map_result/2 % Not tail-recursive |
| 14 | , first_match/2 |
| 15 | , divide/2 |
| 16 | ]). |
| 17 | |
| 18 | -define(DEFAULT_RECURSION_LIMIT, 1000). |
| 19 | |
| 20 | -type t(A) :: |
| 21 | [A]. |
| 22 | |
| 23 | %% @doc Tail-recursive equivalent of lists:map/2 |
| 24 | %% @end |
| 25 | -spec map([A], fun((A) -> (B))) -> |
| 26 | [B]. |
| 27 | map(Xs, F) -> |
| 28 | map(Xs, F, ?DEFAULT_RECURSION_LIMIT). |
| 29 | |
| 30 | -spec map([A], fun((A) -> (B)), RecursionLimit :: non_neg_integer()) -> |
| 31 | [B]. |
| 32 | map(Xs, F, RecursionLimit) -> |
| 33 | map(Xs, F, RecursionLimit, 0). |
| 34 | |
| 35 | map([], _, _, _) -> |
| 36 | []; |
| 37 | map([X1], F, _, _) -> |
| 38 | Y1 = F(X1), |
| 39 | [Y1]; |
| 40 | map([X1, X2], F, _, _) -> |
| 41 | Y1 = F(X1), |
| 42 | Y2 = F(X2), |
| 43 | [Y1, Y2]; |
| 44 | map([X1, X2, X3], F, _, _) -> |
| 45 | Y1 = F(X1), |
| 46 | Y2 = F(X2), |
| 47 | Y3 = F(X3), |
| 48 | [Y1, Y2, Y3]; |
| 49 | map([X1, X2, X3, X4], F, _, _) -> |
| 50 | Y1 = F(X1), |
| 51 | Y2 = F(X2), |
| 52 | Y3 = F(X3), |
| 53 | Y4 = F(X4), |
| 54 | [Y1, Y2, Y3, Y4]; |
| 55 | map([X1, X2, X3, X4, X5 | Xs], F, RecursionLimit, RecursionCount) -> |
| 56 | Y1 = F(X1), |
| 57 | Y2 = F(X2), |
| 58 | Y3 = F(X3), |
| 59 | Y4 = F(X4), |
| 60 | Y5 = F(X5), |
| 61 | Ys = |
| 62 | case RecursionCount > RecursionLimit |
| 63 | of true -> map_slow(Xs, F) |
| 64 | ; false -> map (Xs, F, RecursionLimit, RecursionCount + 1) |
| 65 | end, |
| 66 | [Y1, Y2, Y3, Y4, Y5 | Ys]. |
| 67 | |
| 68 | %% @doc lists:reverse(map_rev(L, F)) |
| 69 | %% @end |
| 70 | -spec map_slow([A], fun((A) -> (B))) -> |
| 71 | [B]. |
| 72 | map_slow(Xs, F) -> |
| 73 | lists:reverse(map_rev(Xs, F)). |
| 74 | |
| 75 | %% @doc Tail-recursive alternative to lists:map/2, which accumulates and |
| 76 | %% returns list in reverse order. |
| 77 | %% @end |
| 78 | -spec map_rev([A], fun((A) -> (B))) -> |
| 79 | [B]. |
| 80 | map_rev(Xs, F) -> |
| 81 | map_rev_acc(Xs, F, []). |
| 82 | |
| 83 | -spec map_rev_acc([A], fun((A) -> (B)), [B]) -> |
| 84 | [B]. |
| 85 | map_rev_acc([], _, Ys) -> |
| 86 | Ys; |
| 87 | map_rev_acc([X|Xs], F, Ys) -> |
| 88 | Y = F(X), |
| 89 | map_rev_acc(Xs, F, [Y|Ys]). |
| 90 | |
| 91 | -spec map_result([A], fun((A) -> (hope_result:t(B, C)))) -> |
| 92 | hope_result:t([B], C). |
| 93 | map_result([], _) -> |
| 94 | {ok, []}; |
| 95 | map_result([X | Xs], F) -> |
| 96 | case F(X) |
| 97 | of {ok, Y} -> |
| 98 | case map_result(Xs, F) |
| 99 | of {ok, Ys} -> |
| 100 | {ok, [Y | Ys]} |
| 101 | ; {error, _}=Error -> |
| 102 | Error |
| 103 | end |
| 104 | ; {error, _}=Error -> |
| 105 | Error |
| 106 | end. |
| 107 | |
| 108 | -spec unique_preserve_order(t(A)) -> |
| 109 | t(A). |
| 110 | unique_preserve_order(L) -> |
| 111 | PrependIfNew = |
| 112 | fun (X, Xs) -> |
| 113 | case lists:member(X, Xs) |
| 114 | of true -> Xs |
| 115 | ; false -> [X | Xs] |
| 116 | end |
| 117 | end, |
| 118 | lists:reverse(lists:foldl(PrependIfNew, [], L)). |
| 119 | |
| 120 | -spec first_match([{Tag, fun((A) -> boolean())}], A) -> |
| 121 | hope_option:t(Tag). |
| 122 | first_match([], _) -> |
| 123 | none; |
| 124 | first_match([{Tag, F} | Tests], X) -> |
| 125 | case F(X) |
| 126 | of true -> {some, Tag} |
| 127 | ; false -> first_match(Tests, X) |
| 128 | end. |
| 129 | |
| 130 | %% @doc Divide list into sublists of up to a requested size + a remainder. |
| 131 | %% Order unspecified. Size < 1 raises an error: |
| 132 | %% `hope_list__divide__size_must_be_a_positive_integer' |
| 133 | %% @end |
| 134 | -spec divide([A], pos_integer()) -> |
| 135 | [[A]]. |
| 136 | divide(_, Size) when Size < 1 orelse not is_integer(Size) -> |
| 137 | % Q: Why? |
| 138 | % A: For N < 0, what does it mean to have a negative-sized chunk? |
| 139 | % For N = 0, we can imagine that a single chunk is an empty list, but, |
| 140 | % how many such chunks should we produce? |
| 141 | % This is pretty-much equivalnet to the problem of deviding something by 0. |
| 142 | error(hope_list__divide__size_must_be_a_positive_integer); |
| 143 | divide([], _) -> |
| 144 | []; |
| 145 | divide([X1 | Xs], MaxChunkSize) -> |
| 146 | MoveIntoChunks = |
| 147 | fun (X2, {Chunk, Chunks, ChunkSize}) when ChunkSize >= MaxChunkSize -> |
| 148 | {[X2], [Chunk | Chunks], 1} |
| 149 | ; (X2, {Chunk, Chunks, ChunkSize}) -> |
| 150 | {[X2 | Chunk], Chunks, ChunkSize + 1} |
| 151 | end, |
| 152 | {Chunk, Chunks, _} = lists:foldl(MoveIntoChunks, {[X1], [], 1}, Xs), |
| 153 | [Chunk | Chunks]. |