module List = ListLabels type color = R | B type ('k, 'v) t = | Leaf | Node of color * ('k * 'v) * ('k, 'v) t * ('k, 'v) t let empty = Leaf let set t ~k ~v = let balance = function | Leaf -> assert false (* LL *) | Node (B, x, Node (R, lx, Node (R, llx, lll, llr), lr ), r ) -> Node (R, lx , Node (B, llx, lll, llr), Node (B, x , lr , r )) (* LR *) | Node (B, x, Node (R, lx, ll , Node (R, lrx, lrl, lrr)), r ) -> Node (R, lrx, Node (B, lx , ll , lrl), Node (B, x , lrr, r )) (* RL *) | Node (B, x, l , Node (R, rx, Node (R, rlx, rll, rlr), rr )) -> Node (R, rlx, Node (B, x , l , rll), Node (B, rx , rlr, rr )) (* RR *) | Node (B, x, l , Node (R, rx, rl , Node (R, rrx, rrl, rrr))) -> Node (R, rx , Node (B, x , l , rl ), Node (B, rrx, rrl, rrr)) | node -> node (* Fragile pattern. Shall we reconsider? *) in let rec set t k v = match t with (* Because we recur, we cannot at this stage know if the following Node * with Leaf children will end-up as root (in which case it should be * black) or as the last node before leaves (in which case it should be * red). We begin by assuming that it is the later and at the very end, * before returning to the caller, force the actual root node (which is * easy to identify at that point) to be black, regardless of what it * already is. *) | Leaf -> Node (R, (k, v), Leaf, Leaf) (* Maybe root or last node, so R *) | Node (c, ((k', _) as x), l, r) when k < k' -> balance (Node (c, x, set l k v, r)) | Node (c, ((k', _) as x), l, r) when k > k' -> balance (Node (c, x, l , set r k v)) | Node (c, _ , l, r) -> Node (c, (k, v), l, r) in match set t k v with | Leaf -> assert false (* Can we GADT this away? *) | Node (_, (k, v), l, r) -> Node (B, (k, v), l, r) (* Root is always Black *) let rec get t ~k = match t with | Leaf -> None | Node (_, (k', _), l, _) when k < k' -> get l ~k | Node (_, (k', _), _, r) when k > k' -> get r ~k | Node (_, (_ , v), _, _) -> Some v let rec member t ~k = match t with | Leaf -> false | Node (_, (k', _), l, _) when k < k' -> member l ~k | Node (_, (k', _), _, r) when k > k' -> member r ~k | Node (_, (_ , _), _, _) -> true let to_edges t = let rec to_edges_from node1 t = match t with | Leaf -> [(node1, `Leaf)] | Node (c2, (k2, _), l, r) -> let node2 = k2, c2 in (node1, `Node node2) :: ((to_edges_from node2 l) @ (to_edges_from node2 r)) in match t with | Leaf -> [] | Node (c, (k, _), l, r) -> let node1 = k, c in (to_edges_from node1 l) @ (to_edges_from node1 r) let color_to_string = function | B -> "black" | R -> "red" let to_dot t ~k_to_string = let (dot_edges_and_nodes, _, _) = List.fold_left (to_edges t) ~init:("", "\n", 0) ~f:(fun (dot_edges_and_nodes, sep, leaves) ((k1, c1), node2_or_leaf) -> let k1 = k_to_string k1 in let k2, c2, leaves = match node2_or_leaf with | `Leaf -> let leaves = succ leaves in let label = Printf.sprintf "Leaf_%d" leaves in (label, B, leaves) | `Node (k2, c2) -> let label = k_to_string k2 in (label, c2, leaves) in let dot_edges_and_nodes = Printf.sprintf "%s%s %S -> %S;\n %S [color=%s,fontcolor=white,style=filled];\n %S [color=%s,fontcolor=white,style=filled];\n" dot_edges_and_nodes sep k1 k2 k1 (color_to_string c1) (* Yes, it's redundant... *) k2 (color_to_string c2) in let sep = "" in (dot_edges_and_nodes, sep, leaves) ) in "digraph G {" ^ dot_edges_and_nodes ^ "}" let of_list pairs = List.fold_left pairs ~init:empty ~f:(fun t (k, v) -> set t ~k ~v) let rec to_list = function | Leaf -> [] | Node (_, pair, left, right) -> pair :: ((to_list left) @ (to_list right))