X-Git-Url: https://git.xandkar.net/?a=blobdiff_plain;f=src%2Fhope_list.erl;h=b5edf42cee87533dc8d630334a175c78b7326756;hb=HEAD;hp=f179d1a054a2dabb46351eef14bf81e64aa9bc8f;hpb=a626cf31904f7d782c8c9756adc4279b0dd5db66;p=hope.git diff --git a/src/hope_list.erl b/src/hope_list.erl index f179d1a..b5edf42 100644 --- a/src/hope_list.erl +++ b/src/hope_list.erl @@ -10,17 +10,16 @@ , map/3 % Tunable recursion limit , map_rev/2 , map_slow/2 + , map_result/2 % Not tail-recursive , first_match/2 + , divide/2 ]). - -define(DEFAULT_RECURSION_LIMIT, 1000). - -type t(A) :: [A]. - %% @doc Tail-recursive equivalent of lists:map/2 %% @end -spec map([A], fun((A) -> (B))) -> @@ -66,7 +65,6 @@ map([X1, X2, X3, X4, X5 | Xs], F, RecursionLimit, RecursionCount) -> end, [Y1, Y2, Y3, Y4, Y5 | Ys]. - %% @doc lists:reverse(map_rev(L, F)) %% @end -spec map_slow([A], fun((A) -> (B))) -> @@ -74,7 +72,6 @@ map([X1, X2, X3, X4, X5 | Xs], F, RecursionLimit, RecursionCount) -> map_slow(Xs, F) -> lists:reverse(map_rev(Xs, F)). - %% @doc Tail-recursive alternative to lists:map/2, which accumulates and %% returns list in reverse order. %% @end @@ -91,6 +88,22 @@ map_rev_acc([X|Xs], F, Ys) -> Y = F(X), map_rev_acc(Xs, F, [Y|Ys]). +-spec map_result([A], fun((A) -> (hope_result:t(B, C)))) -> + hope_result:t([B], C). +map_result([], _) -> + {ok, []}; +map_result([X | Xs], F) -> + case F(X) + of {ok, Y} -> + case map_result(Xs, F) + of {ok, Ys} -> + {ok, [Y | Ys]} + ; {error, _}=Error -> + Error + end + ; {error, _}=Error -> + Error + end. -spec unique_preserve_order(t(A)) -> t(A). @@ -113,3 +126,28 @@ first_match([{Tag, F} | Tests], X) -> of true -> {some, Tag} ; false -> first_match(Tests, X) end. + +%% @doc Divide list into sublists of up to a requested size + a remainder. +%% Order unspecified. Size < 1 raises an error: +%% `hope_list__divide__size_must_be_a_positive_integer' +%% @end +-spec divide([A], pos_integer()) -> + [[A]]. +divide(_, Size) when Size < 1 orelse not is_integer(Size) -> + % Q: Why? + % A: For N < 0, what does it mean to have a negative-sized chunk? + % For N = 0, we can imagine that a single chunk is an empty list, but, + % how many such chunks should we produce? + % This is pretty-much equivalnet to the problem of deviding something by 0. + error(hope_list__divide__size_must_be_a_positive_integer); +divide([], _) -> + []; +divide([X1 | Xs], MaxChunkSize) -> + MoveIntoChunks = + fun (X2, {Chunk, Chunks, ChunkSize}) when ChunkSize >= MaxChunkSize -> + {[X2], [Chunk | Chunks], 1} + ; (X2, {Chunk, Chunks, ChunkSize}) -> + {[X2 | Chunk], Chunks, ChunkSize + 1} + end, + {Chunk, Chunks, _} = lists:foldl(MoveIntoChunks, {[X1], [], 1}, Xs), + [Chunk | Chunks].